## Algebra 1

$\frac{3}{7}=\frac{c+4}{35}$ multiply both sides by 35 $\frac{3}{7}\times35=\frac{c+4}{35}\times35$ simplify $\frac{105}{7}=c+4$ subtract 4 from both sides $15-4=c+4-4$ simplify $11=c$