Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-3 Measures of Central Tendency and Dispersion - Practice and Problem-Solving Exercises: 20

Answer

Mean: 8.83+5=13.83 Median: 9+5=14 Mode: 9+5=14 Range: 8

Work Step by Step

Without given operation: To find the mean, we add up all of the values and divide by the total number of values. Mean: $\frac{3+7+9+9+12+13}{6} = 8.83$ To find the median, we order up all of the values from least to greatest and find the middle number. If there are an even total number of terms, then we take the average of the two terms that are closest to the middle. Median: $3, 7, 9, 9, 12, 13 \rightarrow \frac{9+9}{2} = 9$ To find the mode, we determine the number that shows up the most. Mode: $9$ To find the range, we subtract the smallest term from the largest term. Range: $13-5=8$ From rules involving operations on sets of data, we know that adding a constant value to each term is the same as adding the constant value to the mean, median, and mode of the original set of data. Mean: 8.83+5=13.83 Median: 9+5=14 Mode: 9+5=14 Range: 8
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