Answer
a)
Plant A mean: 57.875
Plant A median: 57.5
Plant A mode: 54
Plant A range: 12
Plant B mean: 55.625
Plant B median: 54.5
Plant B mode: none
Plant B range: 29
b)
Plant A: Mean (highest value)
Plant B: Mean (highest value)
c) Plant A has better control. The range is less than Plant B's range, and both the mean and median are higher than Plant B.
Work Step by Step
a)
Plant A:
$52, 54, 54, 57, 58, 61, 63, 64$
mode = most often
54 shows up twice in the set
median = middle
$52, 54, 54, 57, 58, 61, 63, 64$
$54, 54, 57, 58, 61, 63$
$54, 57, 58, 61$
$57, 58$
$57.5$
mean = average
$(52+54+54+57+58+61+63+64)/8$
$463/8 = 57.875$
range = max - min
range = 64- 52
range = 12
Plant B:
$43, 45, 49, 52, 57, 63, 64, 72$
mode = most often
No mode as all data points are listed once
median = middle
$43, 45, 49, 52, 57, 63, 64, 72$
$45, 49, 52, 57, 63, 64$
$49, 52, 57, 63$
$52, 57$
$(52+57)/2 = 54.5$
range = max- min
range = 72-43
range = 29
mean = average
$(43+45+49+52+57+63+64+72)/8$
$445/8$
$55.625$
