Algebra 1

Published by Prentice Hall

Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 683: 26

Answer

$c=-10$

Work Step by Step

Given: $4(c+25)=c(c+4)$ $4c+100=c^2+4c$ $c^2+4c-4c-100=0$ $c^2-100=0$ $(c^2-10^2)=0$ As we know, $(a^2-b^2)=(a-b)(a+b)$ $(c-10)(c+10)=0$ Solutions are: $c=10,-10x=3,-1$ For $c=10$ the equation does not satisfied so the suitable answer is $c=-10$

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