## Algebra 1

$a=-4$
Given: $3(3+a)=\frac{6a}{3}+5$ $9+3a=\frac{6a}{3}+5$ $\implies (9+3a)3=6a+15$ $\implies 27+9a=6a+15$ $\implies 9a-6a=15-27$ or, $3a=-12$ $\implies a=-4$