Work Step by Step
Given: $8=t(t-2)$ $8=t^2-2t$ $\implies t^2-2t-8=0$ $\implies t^2+2t-4t-8=0$ $\implies t(t-2)+4(t-2)=0$ $\implies (t+2)(t-4)=0$ Solutions are: $t=4,-2$
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