Answer
$z=-\frac{2}{3}$
Work Step by Step
Given: $z^2-(z+2)=z(z+2)$
$z^2-z-2=z^2+2z$
$\implies z^2-z^2-2z-z-2=0$
$\implies -3z-2=0$
$\implies 3z+2=0$
or, $3z=-2 \implies z=-\frac{2}{3}$
$\implies z=-\frac{2}{3}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 683: 22
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