Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-3 Operations with Radial Expressions - Page 643: 36



Work Step by Step

3 inches long $(1+\sqrt5)/2$ $(1+\sqrt5)/2=3/x$ $6 = (1+\sqrt5)x$ $6/(1+\sqrt5) = (1+\sqrt5)x/(1+\sqrt5)$ $6/(1+\sqrt5) = x$ $6/(1+\sqrt5)$ $6/(1+\sqrt5) *(1-\sqrt5)/(1-\sqrt5))$ $6*(1-\sqrt5)/(1-\sqrt5+\sqrt5-5)$ $6*(1-\sqrt5)/-4$ $-3*(1-\sqrt5)/2$
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