Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-3 Operations with Radial Expressions - Page 643: 33

Answer

$4-2\sqrt{10}$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, the given expression is equivalent to $$\begin{aligned} & (3\sqrt{2})(4\sqrt{2})+(3\sqrt{2})(2\sqrt{5})-(2\sqrt{5})(4\sqrt{2})-(2\sqrt{5})(2\sqrt{5}) \\&= 12(2)+6\sqrt{10}-8\sqrt{10}-4(5) \\&= 24+6\sqrt{10}-8\sqrt{10}-20 \\&= 4-2\sqrt{10} .\end{aligned} $$Hence, the given expression simplifies to $4-2\sqrt{10}$.
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