## Algebra 1

$-2+\sqrt3$
Multiply the numerator and denominator by the conjugate and then simplify the radicals: $\frac{\sqrt 3-3}{\sqrt 3+3}\times\frac{(\sqrt 3-3)}{(\sqrt 3-3)}=\frac{\sqrt 9-3\sqrt 3-3\sqrt 3+9}{\sqrt 9-3\sqrt 3+3\sqrt 3-9}=\frac{12-6\sqrt 3}{-6}=-2+\sqrt3$