Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-3 Operations with Radial Expressions - Page 643: 32


$4+2\sqrt 3$

Work Step by Step

We must distribute and then simplify what is under the radicals: $\sqrt 2(\sqrt 8+\sqrt 6)=\sqrt 16+\sqrt 12=4+2\sqrt 3$
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