Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 624: 43



Work Step by Step

$Given,\sqrt (5x+10)=5$ Squaring, $5x+10=25$ $5x+10-10=25-10$ $5x=15$ $x=3$ We need to check by putting the obtained solution in the original equation: $L.H.S=\sqrt (5X3+10)=\sqrt 25=5$ $R.H.S=5$ $L.H.S=R.H.S$,hence it is a valid solution.
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