Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 624: 46

Answer

$a =1, 6$

Work Step by Step

$a = \sqrt {7a-6}$ $a^2 = (\sqrt {7a-6})^2$ $a^2=7a-6$ $a^2-7a+6=7a-6-7a+6$ $(a-6)(a-1) = 0$ $a-6=0$ $a=6$ $a-1=0$ $a=1$ $a^2=7a-6$ $1^2=7*1-6$ $1=7-6$ $1=1$ $a^2=7a-6$ $6^2=7*6-6$ $36 = 42-6$ $36= 36$
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