Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises: 41

Answer

$y=2$

Work Step by Step

$Given,$ $\sqrt (2y) - \sqrt (y+2)=0$ $\sqrt (2y)-\sqrt (y+2) + \sqrt (y+2) = \sqrt (y+2)$ $\sqrt (2y)=\sqrt (y+2)$ Squaring, $2y=y+2$ $2y-y=2$ $y=2$
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