## Algebra 1

$y=2$
$Given,$ $\sqrt (2y) - \sqrt (y+2)=0$ $\sqrt (2y)-\sqrt (y+2) + \sqrt (y+2) = \sqrt (y+2)$ $\sqrt (2y)=\sqrt (y+2)$ Squaring, $2y=y+2$ $2y-y=2$ $y=2$