Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises: 29

Answer

$x=-7$ is extraneous

Work Step by Step

$Given,$ $x=\sqrt (28-3x)$ Checking for $x=-7$: $L.H.S=-7$ $R.H.S=\sqrt (28-3X(-7))=\sqrt (28+21)=\sqrt 49=7$ $L.H.S$ does not equal $R.H.S$,hence extraneous Checking for $x=4$: $L.H.S=4$ $R.H.S=\sqrt (28-3X4)=\sqrt (28-12)=\sqrt 16=4$ $L.H.S=R.H.S$,hence not extraneous
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