## Algebra 1

$\frac{2 ± \sqrt 10}{3}$
The trinomial cannot be factored so we use the quadratic formula to calculate the x. $x= \frac{-b ± \sqrt (b^{2} - 4ac)}{2a}$ $3y^{2} - 4y - 2$ In this trinomial a = 3, b= -4 and c= -2 $x= \frac{-(-4) ± \sqrt (-4^{2} - 4(3)(-2))}{2(3)}$ $x= \frac{4 ± \sqrt (16 + 24)}{6}$ We add the 16 and 24 together $x= \frac{4 ± \sqrt (40)}{6}$ Square root of 40 is $2\sqrt 10$ because the factors of 10 are 4 and 5; and 4 is a perfect square of 2. $x= \frac{4 ± 2\sqrt 10}{6}$ We simplify the numbers to get the final x value. $x= \frac{2 ± \sqrt 10}{3}$