Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises: 64

Answer

$-\sqrt3$

Work Step by Step

$\frac{-3\sqrt2}{\sqrt6}\longrightarrow$ multiply numerator and denominator by $\sqrt6$ =$\frac{-3\sqrt2}{\sqrt6}\times\frac{\sqrt6}{\sqrt6}\longrightarrow$ simplify, multiplication property of square roots =$\frac{-3\sqrt{12}}{\sqrt{36}}\longrightarrow$ factor perfect square out of 12 =$\frac{-3\sqrt{4\times3}}{\sqrt{36}}\longrightarrow$ multiplication property of square roots =$\frac{-3\times\sqrt{4}\times\sqrt3}{\sqrt{36}}\longrightarrow$ simplify =$\frac{-3\times2\times\sqrt3}{6}\longrightarrow$ simplify =$\frac{-6\sqrt3}{6}\longrightarrow$ simplify =$-\sqrt3$
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