## Algebra 1

$d = \sqrt \frac{3h}{2}$ a) Height : 150 ft We substitute the height into the equation. $d = \sqrt \frac{3(150)}{2}$ $\sqrt 225$ = 15 miles Height : 225 ft We substitute the height into the equation. $d = \sqrt \frac{3(225)}{2}$ $\sqrt 337.5$ =18 miles Height : 300 ft We substitute the height into the equation. $d = \sqrt \frac{3(300)}{2}$ $\sqrt 450$ =21 miles b) As the height goes from 150 to 225 the height increases by 75 feet, and the distances goes from 15 to 18 miles, the distance increases by about 3 miles. Therefore as the height increases by 75 feet, the distance increases by about 3 miles.