Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises: 43

Answer

$\frac{\sqrt 10x}{4x}$

Work Step by Step

$\frac{\sqrt 5}{\sqrt 4 \sqrt 2x}$ Square root of 4 is 2 because 2 x 2 = 4 $\frac{\sqrt 5}{2 \sqrt 2x}$ To simplify this, we cannot have a radical in the denominator. We multiply $\frac{\sqrt 5}{2 \sqrt 2x}$ by $\frac{ \sqrt 2x}{ \sqrt 2x}$ $\frac{\sqrt 5}{2 \sqrt 2x} \times \frac{\sqrt 2x}{ \sqrt 2x}$ $\frac{\sqrt 10x}{2 \sqrt 4x^{2}}$ Square root of $4x^{2}$ is 11 because 2x x 2x = $4x^{2}$ $\frac{\sqrt 10x}{2 \times 2x}$ $\frac{\sqrt 10x}{4x}$
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