## Algebra 1

$\frac{\sqrt 10x}{4x}$
$\frac{\sqrt 5}{\sqrt 4 \sqrt 2x}$ Square root of 4 is 2 because 2 x 2 = 4 $\frac{\sqrt 5}{2 \sqrt 2x}$ To simplify this, we cannot have a radical in the denominator. We multiply $\frac{\sqrt 5}{2 \sqrt 2x}$ by $\frac{ \sqrt 2x}{ \sqrt 2x}$ $\frac{\sqrt 5}{2 \sqrt 2x} \times \frac{\sqrt 2x}{ \sqrt 2x}$ $\frac{\sqrt 10x}{2 \sqrt 4x^{2}}$ Square root of $4x^{2}$ is 11 because 2x x 2x = $4x^{2}$ $\frac{\sqrt 10x}{2 \times 2x}$ $\frac{\sqrt 10x}{4x}$