## Algebra 1

$\frac{\sqrt 3x}{8}$
$\sqrt \frac{3x^{3}}{64x^{2}}$ $x^{3} \div x^{2}$ can be simplified to x $\sqrt \frac{3x}{64}$ We can rewrite it as $\frac{\sqrt 3x}{\sqrt 64}$ Square root of 64 is 8 because 8 x 8 = 64 $\frac{\sqrt 3x}{8}$