Algebra 1

Published by Prentice Hall

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 610: 39

Answer

$\frac{\sqrt 3x}{8}$

Work Step by Step

$\sqrt \frac{3x^{3}}{64x^{2}}$ $x^{3} \div x^{2}$ can be simplified to x $\sqrt \frac{3x}{64}$ We can rewrite it as $\frac{\sqrt 3x}{\sqrt 64}$ Square root of 64 is 8 because 8 x 8 = 64 $\frac{\sqrt 3x}{8}$

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