Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises: 28

Answer

$105c \sqrt 3c$

Work Step by Step

$(3 \sqrt 5c) \times (7 \sqrt 15c^{2}) $ We multiply the constants 7 and 3. We multiply the numbers inside the square root. $(3)(7) (\sqrt (5c \times 15c^{2}))$ $21 \sqrt 75c^{3}$ $75c^{3}$ has the factors of $25c^{2} \times 3c$. $21 \sqrt (25c^{2} \times 3c)$ $25c^{2}$ is a perfect square. Square root of $25c^{2}$ is 5c. Because 5c x 5c = $25c^{2}$ $(21)(5c) \sqrt 3c$ $105c \sqrt 3c$
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