Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises: 31

Answer

$-126a \sqrt a$

Work Step by Step

$-9 \times \sqrt 4 \times \sqrt (7a^{2}) \times \frac{1}{3} \times \sqrt 9 \times \sqrt 7a $ *** $ \sqrt 4$ = 2 because $2 \times 2$ = 4 *** $ \sqrt a^{2}$ = a because $a \times a = a^{2}$ *** $ \sqrt 9$ = 3 because $3 \times 3$ = 9 $-9 \times 2 \times a \times \sqrt 7 \times \frac{1}{3} \times 3 \times \sqrt 7a $ We multiply the constants together and the numbers in the square root rogether $-18a \times \sqrt 49a$ 49 is a perfect square because 7 x 7 = 49 $-18a \times 7 \times \sqrt a$ $-126a \times \sqrt a$ $-126a \sqrt a$
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