## Algebra 1

$-126a \sqrt a$
$-9 \times \sqrt 4 \times \sqrt (7a^{2}) \times \frac{1}{3} \times \sqrt 9 \times \sqrt 7a$ *** $\sqrt 4$ = 2 because $2 \times 2$ = 4 *** $\sqrt a^{2}$ = a because $a \times a = a^{2}$ *** $\sqrt 9$ = 3 because $3 \times 3$ = 9 $-9 \times 2 \times a \times \sqrt 7 \times \frac{1}{3} \times 3 \times \sqrt 7a$ We multiply the constants together and the numbers in the square root rogether $-18a \times \sqrt 49a$ 49 is a perfect square because 7 x 7 = 49 $-18a \times 7 \times \sqrt a$ $-126a \times \sqrt a$ $-126a \sqrt a$