Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 606: 60


The solutions of the system are $(-9,33)$ and $(-12,63)$.

Work Step by Step

$ y=-10x-57$ $y=x^2+11x+51$ Substitute $-10x-57$ for y $-10x-57=x^2+11x+51$ $x^2+21x+108=0$ $(x+9)(x+12)=0$ $x+9=0$ or $x+12=0$ $x=-9$ or $x=-12$ Find corresponding y-values. Use either original equation: $ y=-10x-57$ $=-10(-9)-57$ or $ y=-10(-12)-57$ $y=33$ or $y=63$ The solutions of the system are $(-9,33)$ and $(-12,63)$.
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