Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 606: 55


The solutions of the system are $(-8,3)$ and $(12,123)$.

Work Step by Step

$y=6x+51$ $y=x^2+2x-45$ Substitute $6x+51$ for y $6x+51=x^2+2x-45$ $x^2-4x-96=0$ $(x-12)(x+8)=0$ $x+8=0$ or $x-12=0$ $x=-8$ or $x=12$ Find corresponding y-values. Use either original equation $y=6x+51$ $y=6(-8)+51$ or $y=6(12)+51$ $y=3$ or $y=123$ The solutions of the system are $(-8,3)$ and $(12,123)$.
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