#### Answer

The solutions of the system are $(-4,-21)$ and $(-7,-45)$.

#### Work Step by Step

$y-11=8x \rightarrow y=8x+11$
$y=x^2+19x+39$
Substitute $8x+11$ for y
$8x+11=x^2+19x+39$
$x^2+11x+28=0$
$(x+4)(x+7)=0$
$x+4=0$ or $x+7=0$
$x=-4$ or $x=-7$
Find corresponding y-values. Use either original equation
$y=8x+11$
$y=8(-4)+11$ or $y=8(-7)+11$
$y=-21$ or $y=-45$
The solutions of the system are $(-4,-21)$ and $(-7,-45)$.