Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 606: 57


The solutions of the system are $(-4,-21)$ and $(-7,-45)$.

Work Step by Step

$y-11=8x \rightarrow y=8x+11$ $y=x^2+19x+39$ Substitute $8x+11$ for y $8x+11=x^2+19x+39$ $x^2+11x+28=0$ $(x+4)(x+7)=0$ $x+4=0$ or $x+7=0$ $x=-4$ or $x=-7$ Find corresponding y-values. Use either original equation $y=8x+11$ $y=8(-4)+11$ or $y=8(-7)+11$ $y=-21$ or $y=-45$ The solutions of the system are $(-4,-21)$ and $(-7,-45)$.
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