Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 606: 59


The solutions of the system are $(10,145)$ and $(6,69)$.

Work Step by Step

$y+45=19x \rightarrow y=19x-45$ $y=x^2+3x+15$ Substitute $19x-45$ for y $19x-45=x^2+3x+15$ $x^2-16x=60=0$ $(x-10)(x+13)=0$ $x-10=0$ or $x-6=0$ $x=10$ or $x=6$ Find corresponding y-values. Use either original equation $ y=19x-45$ $=19(10)-45$ or $ y=19(6)-45$ $y=145$ or $y=69$ The solutions of the system are $(10,145)$ and $(6,69)$
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