Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 17

Answer

$(2m-1)(2m+1)(2m+3)$

Work Step by Step

$8m^{3}+12m^{2}-2m-3=$ ...factor out the GCF of each group of two terms. $=4m^{2}(2m+3)-1(2m+3)$ ...factor out the common factor, $2m+3$. $=(4m^{2}-1)(2m+3)$ ...write $4m^{2}-1$ as a difference of two squares. $=(2m-1)(2m+1)(2m+3)$
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