Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 14

Answer

$(2y^2+1)(7y+4)$

Work Step by Step

$14y^3+8y^2+7y+4$ Factor out the GCF of each group of two terms. $=7y(2y^2+1)+4(2y^2+1)$ Factor out the common factor, $(2y^2+1)$ $=(2y^2+1)(7y+4)$
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