## Algebra 1: Common Core (15th Edition)

$(2y^2+1)(7y+4)$
$14y^3+8y^2+7y+4$ Factor out the GCF of each group of two terms. $=7y(2y^2+1)+4(2y^2+1)$ Factor out the common factor, $(2y^2+1)$ $=(2y^2+1)(7y+4)$