Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 16



Work Step by Step

$11w^{3}-9w^{2}+11w-9=$ ...factor out the GCF of each group of two terms. $=w^{2}(11w-9)+1(11w-9)$ ...factor out the common factor, $11w-9$. $=(w^{2}+1)(11w-9)$
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