Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 15

Answer

$(7z^{2}+8)(2z-5)$

Work Step by Step

$14z^{3}-35z^{2}+16z-40=$ ...factor out the GCF of each group of two terms. $=7z^{2}(2z-5)+8(2z-5)$ ...factor out the common factor, $2z-5$. $=(7z^{2}+8)(2z-5)$
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