Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 476: 50



Work Step by Step

You have the expression ($\frac{5a^8}{10a^6}$$)^{-3}$.Simplify the expression: ($\frac{5a^8}{10a^6}$$)^{-3}$=($\frac{10a^6}{15a^8}$$)^{3}$ -Use the rule $a^{-b}$=$\frac{1}{a^b}$- (2$a^{6-8}$$)^{3}$ -divide 10 and 5 to get 2 then subtract exponents with the same base- (2$a^{-2}$$)^{3}$ -Use the rule $a^{-b}$=$\frac{1}{a^b}$- ($\frac{2}{a^2}$$)^{3}$ -raise the denominator to the power(3)- =$\frac{8}{a^6}$
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