Algebra 1: Common Core (15th Edition)

$(4x^3y^5)^2=16x^6y^{10}$
$(4x^3y^5)^x=16x^6y^{10}$ $(4x^3y^5)^x=(4x^3y^5)^2$ $x=2$ Thus, the completed equation is: $(4x^3y^5)^2=16x^6y^{10}$