Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 476: 32



Work Step by Step

$(4x^3y^5)^x=16x^6y^{10}$ $(4x^3y^5)^x=(4x^3y^5)^2$ $x=2$ Thus, the completed equation is: $(4x^3y^5)^2=16x^6y^{10}$
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