## Algebra 1: Common Core (15th Edition)

7$x^{4}$
You have the expression $\frac{21x^3}{3x^-1}$.Simplify the expression: (7$\div$3)($x^{3-(-1)}$) -divide 21 and 3 to get 7 and then subtract the exponents because you are dividing powers with the same base- =7$x^{4}$