Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 476: 43



Work Step by Step

You have the expression $\frac{21x^3}{3x^-1}$.Simplify the expression: (7$\div$3)($x^{3-(-1)}$) -divide 21 and 3 to get 7 and then subtract the exponents because you are dividing powers with the same base- =7$x^{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.