Answer
$\frac{243}{16}x^{3}y^{11}$
Work Step by Step
$(12x^2y^{-2})^5(4xy^{-3})^{-7}$
$=((4.3)x^2y^{-2})^5(4xy^{-3})^{-7}$
$=(4^5.3^5x^{10}y^{-10})(4^{-7}x^{-7}y^{21})$
$=4^{-2}3^5x^{3}y^{11}$
$=\frac{243}{16}x^{3}y^{11}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 476: 38
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