Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 442: 23

Answer

$\frac{3b^7}{a^6c^8}$

Work Step by Step

You have $\frac{12b^6b^1}{4a^5a^1c^5c^3}$.Solve: $\frac{12b^6b^1}{4a^5a^1c^5c^3}$ -add exponents with the same base- $\frac{12b^7}{4a^6c^8}$ -divide what can be divided- =$\frac{3b^7}{a^6c^8}$
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