## Algebra 1: Common Core (15th Edition)

You have $\frac{(5^2)(5^3)}{(5^3)(5^2)}$. Solve: $\frac{5^2*5^3}{5^3*5^2}$ -remove the parentheses and add the exponents since you are multiplying them- $\frac{5^5}{5^5}$ -apply the rule that $\frac{a}{a}$=1- =1 So, the blank should be filled with 0 as any number to the zeroth power is 1.