Answer
3
Work Step by Step
You have $\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$. Solve it:
$\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$ -apply exponent rule $\frac{x^a}{x^b}$=$x^{a-b}$-
$\frac{3}{4}$-$\frac{1}{4}$=$\frac{1}{2}$
$9^{1/2}$ -when a number is raised to a half it is basically like having to find its square root-
$\sqrt 9$
=3
