## Algebra 1: Common Core (15th Edition)

You have $\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$. Solve it: $\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$ -apply exponent rule $\frac{x^a}{x^b}$=$x^{a-b}$- $\frac{3}{4}$-$\frac{1}{4}$=$\frac{1}{2}$ $9^{1/2}$ -when a number is raised to a half it is basically like having to find its square root- $\sqrt 9$ =3