Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 442: 13



Work Step by Step

You have $\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$. Solve it: $\frac{9^3{^/}{^4}}{9^1{^/}{^4}}$ -apply exponent rule $\frac{x^a}{x^b}$=$x^{a-b}$- $\frac{3}{4}$-$\frac{1}{4}$=$\frac{1}{2}$ $9^{1/2}$ -when a number is raised to a half it is basically like having to find its square root- $\sqrt 9$ =3
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