Answer
$\displaystyle \frac{x^{4}}{y^{1/2}}$
Work Step by Step
$\displaystyle \frac{x^{5}}{x}=x^{5-1}\quad$ .... Dividing powers with the same base
$=x^{4}$
$\displaystyle \frac{y^{-9/2}}{y^{-4}}=y^{-9/2-(-4)}\quad$ .... Dividing powers with the same base
$=y^{-9/2+4}$
$=y^{-1/2}\quad$ .... Negative exponent property
$=\displaystyle \frac{1}{y^{1/2}}$
$\displaystyle \frac{z^{3}}{z^{3}}=z^{3-3}\quad$ .... Dividing powers with the same base
$=z^{0}\quad$ .... Zero exponent property
$=1$
$\displaystyle \text{Problem}=x^{4}\cdot\frac{1}{y^{1/2}}\cdot 1$
= $\displaystyle \frac{x^{4}}{y^{1/2}}$
