Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 383: 41

Answer

The solution is: $x=2$ $y=\frac{-3}{5}$

Work Step by Step

$\frac{2}{x}-\frac{3}{y}=-5$ (1) $\frac{4}{x}+\frac{6}{y}=14$ (2) Eliminate a variable: $\frac{4}{x}-\frac{6}{y}=-10$ (1) $\frac{4}{x}+\frac{6}{y}=14$ (2) ___________________ $\frac{8}{x}=4$ Solve for x: $x=2$ $y=\frac{-3}{5}$
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