## Algebra 1: Common Core (15th Edition)

The solution is: $x=2$ $y=\frac{-3}{5}$
$\frac{2}{x}-\frac{3}{y}=-5$ (1) $\frac{4}{x}+\frac{6}{y}=14$ (2) Eliminate a variable: $\frac{4}{x}-\frac{6}{y}=-10$ (1) $\frac{4}{x}+\frac{6}{y}=14$ (2) ___________________ $\frac{8}{x}=4$ Solve for x: $x=2$ $y=\frac{-3}{5}$