Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 383: 29

Answer

The error that the student made was they did not multiply the last part of the second equation, which is -3, by 4. This is what resulted in the incorrect answer. The first equation should be solved like this: 1st : $5x+4y = 2$ then multiplied by 3 to get $15x+12y = 6$ The second equation should be solved like this: 2nd: $3x+3y = -3$ then multiplied by 4 to get $12x+12y= -12 $ These equations should then be subtracted (the 1st - 2nd) to get $3x= -6$. Dividing both sides by 3 will get the value of $x=-2$. This is the correct solution to this system.

Work Step by Step

See above.
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