## Algebra 1: Common Core (15th Edition)

$y=5$ $x=6$
$y=\frac{2}{3}x+1$ $2x+3y=27$ $-\frac{2}{3}x+y=1$ (1) $2x+3y=27$ (2) Divide both sides of equation (2) by $3$ to obtain: $-\frac{2}{3}x+y=1$ $\frac{2}{3}x+y=9$ ___________________ $2y=10$ $y=5$ $x=6$