Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 383: 37


The solution is: $x=6$ $y=-4$

Work Step by Step

$\frac{1}{3}x+\frac{1}{2}y=0$ (1) $\frac{1}{2}x+\frac{1}{5}y=\frac{11}{5}$ (2) Eliminate a variable: $\frac{1}{6}x+\frac{1}{4}y=0$ (1) $\frac{1}{6}x+\frac{1}{15}y=\frac{11}{15}$ (2) ___________________ $\frac{11}{60}y=-\frac{11}{15}$ Solve for y: $y=-4$ $x=6$
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