## Algebra 1: Common Core (15th Edition)

$x=5, y=2$
To solve this system, first simply the first equation so that x is separated on the other side of the '=' symbol. Then, substitute 'y+3' for x in the second equation, and solve. After getting the 'y' value, substitute that into the first equation, and you can get the 'x' value. $4y+3=3y+x = x=y+3$ $2x+4y=18$ $2(y+3)+4y=18$ $2y+6+4y=18$ $6y+6=18$ $6y=12$ $y=2$ $x=y+3$ $x=2+3$ $x=5$