## Algebra 1: Common Core (15th Edition)

We know that y=x+3. Thus, in the first equation, wherever we see y, we will substitute x+3, and then we will solve: $2x+2(x+3) =38 \\\\ 4x+6=38 \\\\ 4x=32 \\\\ x=8$ We now substitute x=8 back in: y=8+3=11 We plug (8,11) back into the first equation and confirm that our answer is, indeed, correct.