Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 375: 18



Work Step by Step

You have two equations: 4x=3y-2 and 3x+y=18. Isolate y in the second equation in order to be able to substitute it into the first equation: 3x+y=18 -subtract 3x from both sides- y=-3x+18 Substitute the equation into the first equation: 4x=3y-2 -substitute- 4x=3(-3x+18)-2 -distribute- 4x=-9x+54-2 -simplify like terms- 4x=-9x+52 -add 9x to both sides- 13x=52 -divide both sides by 13- x=4 Plug in x=4 into one of the equations to solve for y: 3(4)+y=18 12+y=18 y=6 The solution is (4,6)
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