## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 375: 17

(-11, -19)

#### Work Step by Step

We first add 2x to both sides of the first equation to obtain that y=2x+3. Thus, in the second equation, wherever we see y, we will substitute 2x+3, and then we will solve: $3x -2(2x+3) = 5 \\\\ -x-6=5 \\\\ -x =11 \\\\ x=-11$ We now substitute x=-11 back in: $y=2(-11)+3=-19$ We plug this point back into the first equation and find that our answer is correct.

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