Algebra 1: Common Core (15th Edition)

We first add 2x to both sides of the first equation to obtain that y=2x+3. Thus, in the second equation, wherever we see y, we will substitute 2x+3, and then we will solve: $3x -2(2x+3) = 5 \\\\ -x-6=5 \\\\ -x =11 \\\\ x=-11$ We now substitute x=-11 back in: $y=2(-11)+3=-19$ We plug this point back into the first equation and find that our answer is correct.