Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises: 32

Answer

1

Work Step by Step

We know that: $_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$ $_3C_0 = \frac{3!}{(3-0)!0!}$ $\frac{ 3!}{3!}$ Which we know is equal to $\underline 1$.
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