Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 766: 16



Work Step by Step

We know that: $_nP_r = \frac{n!}{(n-r)!}$ $_9P_3 = \frac{9!}{(9-3)!}$ $\frac{9!}{6!}$ We also know that: $x! = x(x-1)(x-2)...(1)$ Thus, we have: $\frac{9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}$ = 504
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