#### Answer

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#### Work Step by Step

We know that:
$_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$
$_6C_6 = \frac{6!}{(6-6)!r6!}$
$\frac{6!}{6!}$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
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