Answer
120
Work Step by Step
We know that:
$_nP_r = \frac{n!}{(n-r)!}$
$_5P_5 = \frac{5!}{(5-5)!}$
$\frac{5!}{0!}= 5!$
We also know that:
$x! = x(x-1)(x-2)...(1)$
Thus, we have:
120
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